x^2+96x-100=0

Solution for x^2+96x-100=0 equation:

x^2+96x-100=0

a = 1; b = 96; c = -100;
Δ = b2-4ac
Δ = 962-4·1·(-100)
Δ = 9616
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9616}=\sqrt{16*601}=\sqrt{16}*\sqrt{601}=4\sqrt{601}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(96)-4\sqrt{601}}{2*1}=\frac{-96-4\sqrt{601}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(96)+4\sqrt{601}}{2*1}=\frac{-96+4\sqrt{601}}{2}
$